Wolverine setup with two regulator and one Rx

[Flyfalcons]

Daniel, here is what I would recommend on your setup:

Each Rx battery be equipped with a Deans connector, and if you want, a second JR lead attached to the battery for charging it out of the plane if you need to (if you don't have a Deans lead on your Li-Ion charger).

The Wolverine switch should have two Deans connectors on the battery side, and two Deans connectors on the "receiver/regulator" side.

Each regulator will have one Deans connector going in, and two JR leads going out. That will avoid a power bottleneck of all the battery's power going through one JR connector. With two batts and regulators, you'll have a total of four power leads going into the receiver, which will handle any load you can throw at it. If you don't have enough spare channels to plug all those connectors into, use a Y-harness on some channels like throttle to gain an extra socket to plug the power leads into. Hope that made sense.

[JoeAirPort]

The picture is a little deceiving with the regulators tied together before they get to the rx....but I knew what you meant.

I think it's worth getting an rx with a ton of servo channels to get the 4 JR plugs into it. I don't like Y's. Another thing you could do is just get two smaller receivers.

[Flyfalcons]

The little Y-harnesses like this one do a nice job and take up very little space. I'm using one on my 50cc Edge to run a second power connector into a 7-channel receiver. I plugged it into the throttle channel. A receiver that has more channels to begin with is of course a more elegant solution but this works.

http://www3.towerhobbies.com/cgi-bin...&I=LXH451&P=ML

[JoeAirPort]

Pretty cool. I've never seen one of those.

[kingfd]

	Quote: Originally Posted by Flyfalcons
	Daniel, here is what I would recommend on your setup: Each Rx battery be equipped with a Deans connector, and if you want, a second JR lead attached to the battery for charging it out of the plane if you need to (if you don't have a Deans lead on your Li-Ion charger). The Wolverine switch should have two Deans connectors on the battery side, and two Deans connectors on the "receiver/regulator" side. Each regulator will have one Deans connector going in, and two JR leads going out. That will avoid a power bottleneck of all the battery's power going through one JR connector. With two batts and regulators, you'll have a total of four power leads going into the receiver, which will handle any load you can throw at it. If you don't have enough spare channels to plug all those connectors into, use a Y-harness on some channels like throttle to gain an extra socket to plug the power leads into. Hope that made sense.

I understand what you mean, I do have one Deans connector going in but dont have 2 JR leads going out. I have just one leads that going out so I will have just two leads that goes to the reciever.

So what you recomend? connect each leads connectors to the receiver(one to the battery input connection and one to a spare channel) or to connect it with Y's connector just to the battery input connection?


Daniel

[Flyfalcons]

One to the battery slot, one to a spare channel.

[kingfd]

	Quote: Originally Posted by Flyfalcons
	One to the battery slot, one to a spare channel.

ohhh that was fast thanks!

will do that!

[kingfd]

I just think about something...
If one regulator will give 6V and the other will give 5.9V. It cant do something to the Rx?

Daniel.

anyway I will ask that on futaba direct support forum.

[Flyfalcons]

You're fine. People have been running this setup for years.

[CSpaced]

Yep, this is how I am going to run my edge.

[MattyMatt]

This is the same setup I had in my Extra 260... works great and the wolverine switch will always pull equil amounts of juice from each pack.

[Fromeco]

Kingfd,

You got it correct, as does everyone else giving you advise. I think it was mentioned, if you have an extra open port just plug a regulator in there, "Y's" just add another connection and more resistance.

The one thing that no one mentioned, and is the most important thing you need to do is, make sure your regulators are balanced. In other words make sure they are at the same voltage, get them as close as you can. Remember voltage is like water pressure. Who ever has the highest wins. In the case of regulators you will just have one working harder than the other. This will have no effect on the batteries because you have a Wolverine in the mix. It is best to have the regs as close to equal as possible. You will not be able to get them perfect, but you should be able to get them really close.

A good match would look like this; Left 5.98 Right 5.95
A bad match would look like this; Left 5.98 Right 5.85

Hope that helps, your set up is, "As designed"
Good Flying

Kurt Cook
Fromeco Scale Avionics LLC

[lockit400]

Ok guys help me as well if you can , new to this wiring stuff as well,

I also want to install a simple set up in my 30% 50cc plane ,

So what wolverine switch will I buy and also which 2 regs do I get ,
So many choices on the Fromeco site ,

I was thinking of useing 2 2300 mah a123s , is this over kill ?

or can I just use 1 2300 mah through reg to rec and one for ign ?

lockit400

[CSpaced]

I think a single battery through a reg into the receiver is sufficient for a 50cc sized plane, no need for a wolverine switch - you could just use a badger switch. Using two batteries and two regs would be a good setup for a 100cc sized airplane.

[JoeAirPort]

I use a single batt and switch with a Dean's Ultra on the input and two JR plugs on the output for my 50cc planes. I just use a really good quality switch and a very low impedance battery pack (1950 FAUP 5-cell) and install them right. I never have problems on 5 planes setup like this. No regulators for me.

My next 50cc setup will probably be 2 x A123 1100mah into a Wolverine with two Dean's Ultra inputs and two JR output plugs.